35a^2+41a-24=0

Solution for 35a^2+41a-24=0 equation:

35a^2+41a-24=0

a = 35; b = 41; c = -24;
Δ = b2-4ac
Δ = 412-4·35·(-24)
Δ = 5041
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{5041}=71$
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(41)-71}{2*35}=\frac{-112}{70}
=-1+3/5
$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(41)+71}{2*35}=\frac{30}{70}
=3/7
$